大智慧DLL算法是否和金字塔DLL算法一致

作者：金字塔來源：cxh99.com 發布時間：2021年07月01日

咨詢內容： 大智慧DLL算法是否和金字塔DLL算法一致
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金字塔客服： 基本一致
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?來源:程序化久久網（ www.kzuj.com.cn ）
用戶回復： DLL一致，為什么指標公式復制到指標不能用呢
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網友回復： 請詳細描述一下問題，必要時請貼出公式代碼
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網友回復： 我想把原來在大智慧使用的DLL以及公式代碼復制到金字塔使用，因為大智慧數據不全面，使用同一個DLL，有個別指標達不到原大智慧的效果，你說DLL算法一致，那應該就是公式的問題
kx:="chanlun@kxian"; {這個放第一個要不會出問題滴-_-\\\~~} kxg:="chanlun@kxg"; kxd:="chanlun@kxd"; kxfx:="chanlun@kxfx"; kxno:"chanlun@kxno", linethick0, coloryellow; kxnobh:"chanlun@kxnobh", linethick0, coloryellow; 筆:="chanlun@bi"; bilast:"chanlun@bilast", linethick0, coloryellow; 段:="chanlun@duan"; duanlast:"chanlun@duanlast", linethick0, coloryellow; 中樞:="chanlun@zs"; zszg:="chanlun@zszg"; zszd:="chanlun@zszd"; zsgg:="chanlun@zsgg"; zsdd:="chanlun@zsdd"; zszz:="chanlun@zszz"; zsks:="chanlun@zskslast"; zsjs:="chanlun@zsjslast"; bifx:=-REF(筆,bilast); duanfx:=-REF(段,duanlast);
kxqj:="chanlun@kxqj"; fxqj:ref(kxqj,bilast), linethick0, coloryellow;
{TT:"chanlun@TT", linethick0, colorwhite;}
{畫中樞Begin} {以背景方式畫} { STICKLINE(zszg>zszd AND duanfx=1, zszg, zszd, 20, 502), colorf00ff0; STICKLINE(zszg>zszd AND duanfx=-1, zszg, zszd, 20, 502), colore6002d; } {以直線方式畫} {上漲中樞} DRAWLINE(zsks=1 AND duanfx=1, zszg, zsjs=1 AND duanfx=1, zszg, 0), colormagenta, linethick2; DRAWLINE(zsks=1 AND duanfx=1, zszd, zsjs=1 AND duanfx=1, zszd, 0), colormagenta, linethick2; STICKLINE(zsks=1 AND duanfx=1, zszg, zszd, 1 AND duanfx=1, -501), colormagenta, linethick2; STICKLINE(zsjs=1 AND duanfx=1, zszg, zszd, 1 AND duanfx=1, 501), colormagenta, linethick2; {下跌中樞} DRAWLINE(zsks=1 AND duanfx=-1, zszg, zsjs=1 AND duanfx=-1, zszg, 0), colorCyan, linethick2; DRAWLINE(zsks=1 AND duanfx=-1, zszd, zsjs=1 AND duanfx=-1, zszd, 0), colorCyan, linethick2; STICKLINE(zsks=1 AND duanfx=-1, zszg, zszd, 1 AND duanfx=-1, -501), colorCyan, linethick2; STICKLINE(zsjs=1 AND duanfx=-1, zszg, zszd, 1 AND duanfx=-1, 501), colorCyan, linethick2; {中樞震蕩監視器} DRAWLINE(zsks=1, zszz, zsjs=1, zszz, 0), coloryellow;? {畫中樞END}
{顯示缺口BEGIN} {只顯示5F及5F級別以上圖的缺口} kxqk:="chanlun@kxqk"; {最后未封閉的最后一個上漲（下跌）缺口到現在的周期} kxqkup:BARSLAST(kxqk=1), linethick0, colorMagenta; kxqkdn:BARSLAST(kxqk=-1), linethick0, colorGreen; {缺口} DRAWTEXT(kxqk=1, l*0.992, '☆'), colorMagenta, align1 ; {未封閉上漲缺口} DRAWTEXT(kxqk=2, l*0.992, '★'), colorMagenta, align1 ; {已封閉上漲缺口} DRAWTEXT(kxqk=-1, h*1.008, '☆'), colorGreen, align1, valign2; {未封閉下跌缺口} DRAWTEXT(kxqk=-2, h*1.008, '★'), colorGreen, align1, valign2; {已封閉下跌缺口} {顯示缺口END}
{畫K線Begin} {纏論K線已經包含處理} STICKLINE(kxfx>1, kxg, kxd, 2, 1), coloryellow; STICKLINE(kxfx<1, kxg, kxd, 2, 1), colorF0F000; STICKLINE(kxfx=1, kxg, kxd, 2, 1), colorred; STICKLINE(kxfx=-1, kxg, kxd, 2, 1), colorgreen; {頂底分型} STICKLINE(kx>0, kxg, kxd, 5, 1), colorwhite; STICKLINE(kx<0, kxg, kxd, 5, 1), colorblue; {筆段} STICKLINE(筆=1, kxg, kxd, 5, 1), colorgreen, linethick3; STICKLINE(筆=-1, kxg, kxd, 5, 1), colorred, linethick3; STICKLINE(段=1, kxg, kxd, 5, 0), colore66878, linethick2; STICKLINE(段=-1, kxg, kxd, 5, 0), color00cccc, linethick2; {畫K線END}
{畫筆段} drawline(筆=1,h,筆=-1,l,0),coloryellow; drawline(筆=-1,l,筆=1,h,0),coloryellow; drawline(段=1,h,段=-1,l,0),colorblue, linethick2; drawline(段=-1,l,段=1,h,0),colorblue, linethick2;
{筆高低點周期力度提示} DRAWTEXT(筆=1, h, ''+h+'/T'+bilast+'/+'+(h-REF(l,bilast))), coloryellow, align1, valign2; DRAWTEXT(筆=-1, l, ''+l+'/T'+bilast+'/'+(l-REF(h,bilast))), colorCyan, align1;
{當下提示周期} DRAWTEXT(BARSTATUS=2 AND bifx=1 AND bilast>4, h*1.008, 'T'+bilast+'/+'+(c-REF(l,bilast))), colorMagenta, align0, valign2; DRAWTEXT(BARSTATUS=2 AND bifx=-1 AND bilast>4, l*0.992,'T'+bilast+'/'+(c-REF(h,bilast))), colorGreen, align0;
{布林曲線} { MID :MA(CLOSE,26),pointdot,colorwhite; UPPER:MID + 2*STD(CLOSE,26),linethick1,coloryellow; LOWER:MID - 2*STD(CLOSE,26),linethick1,colorgreen; 收口:=UPPER-LOWER; partline(UPPER,收口>ref(收口,1),rgb(255,255,0),收口<ref(收口,1),rgb(0,255,0)),linethick1, dotline; partline(LOWER,收口>ref(收口,1),rgb(255,255,0),收口<ref(收口,1),rgb(0,255,0)),linethick1, dotline; }
{以下主要演示取筆段中樞數據的方法} {前N個高點和低點(筆)} { bigglast:="chanlun@bigglast"; bigg1:ref(h, bigglast), linethick0, coloryellow; bigg2:ref(bigg1, bigglast), linethick0, coloryellow; bigg3:ref(bigg2, bigglast), linethick0, coloryellow;
biddlast:="chanlun@biddlast"; bidd1:ref(l, biddlast), linethick0, colorcyan; bidd2:ref(bidd1, biddlast), linethick0, colorcyan; bidd3:ref(bidd2, biddlast), linethick0, colorcyan; }
{取前一段的數據} { dgglast:="chanlun@duangglast"; dgg1:ref(h, dgglast),linethick0, coloryellow;
dddlast:="chanlun@duanddlast"; ddd1:ref(l, dddlast),linethick0, colorcyan; }
{取前一個中樞的數據} { zszg1:ref(zszg, zsjs),linethick0, coloryellow; zszd1:ref(zszd, zsjs),linethick0, coloryellow; };
{版本信息Begin} vsnNO:="chanlun@VERSION"; vsnDate:="chanlun@DATE"; vsnSTR:= '版本:'+vsnNO+'.'+vsnDate; {vsnSTR1:= ' 作者:goodpp2012@gmail.com';} vsnSTR1:=''; DRAWTEXTREL( 5, 950, vsnSTR+vsnSTR1), colormagenta, linethick2;

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大智慧DLL算法是否和金字塔DLL算法一致